The displacement of a particle starting from rest (at t=0) is given by s=6t^2-t^3. The time in seconds at which the particle will attain zero velocity again , is
(A) 2. (B) 4. (C) 6. (D) 8.
please show the solution.
Answers
Answered by
3
Hey
Differentiating the above equation
dx/dt = 12t - 3t^2
for v = 0 m/s
0 = 12t - 3t^2
=>3t^2 = 12t
=>3t = 12
=>t = 4 seconds Answer
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Differentiating the above equation
dx/dt = 12t - 3t^2
for v = 0 m/s
0 = 12t - 3t^2
=>3t^2 = 12t
=>3t = 12
=>t = 4 seconds Answer
Hope it helps
Pls mark me brainliset :)
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Answered by
1
displacement of particle is given by...
s=6t^2-t^3
differentiate wrt time..
ds/dt =12t-3t^2
v=12t-3t^2
velocity will be zero..
12t-3t^2=0
t(12-3t)=0
t=0 or 12-3t=0
t=0 or t=4
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