Question

The displacement of a particle varies with time
(t) as: s = at² – bt³. The acceleration of the
particle at any given time (t) will be equal to
(a) a (b) a
b 3b

(c)3b (d) 2a
a 3b

Answer 1

Explanation:

x=at

2

−bt

3

⇒ Velocity =

dt

dx

=2at−3bt

2

Acceleration=

dt

2

d

2

x

=

dt

d

(2at−3b

2

)=2a−6bt

or a=2a−6bt

Making a=0

⇒2a=6bt

⇒t=dfrac2a6b=

3b

a

.