The displacement of a particle x=18t+5t^2 calculate the velocity at 2 avg velocity btw acceleration
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Answer:
GIVEN X=18t+5t^2
t=2
Explanation:
we know that acceleration is calculated by
a=d²x/dt²
=d²/dt²(18t+5t²)
=d/dt(10t+1)
=10 m/s²
v=dx/dt
=d/dt(18t+5t²)
=18+10t
=18+20
=38 m/s
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