the displacement of a particles x=6t³+5t taken from t=0 calculate its Acceleration at t=4 second?
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Answer:
18m/s2
Explanation:
Velocity (v) = d(x)/d(t) = 18t + 5
Acceleration (a) = 18 + 0
Acceleration is independent of time.
Therefore, acceleration (a) = 18 m/s2.
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