Question

the displacement of a particlex varies with time as X = 4t^2 -15t +25 . find the position , velocity and acceleration of the particle at t= 0.​

Answer 1

Given :-

Position of Particle = x = 4t² -15t + 25

Differentiating x w.r.t t to get Velocity.

v = dx/dt

v = d(4t² - 15t + 25)/dt

v = 8t - 15

Again differentiating v w.r.t t to get acceleration of particle.

a = dv/dt

a = d(8t - 15)/dt

a = 8 ms-².

As acceleration is independent of time hence,

Acceleration of particle = a = 8 ms-².