The displacement of an elastic wave is given by the function
y = 3 sin wt + 4 coswt where y is in cm and t is in second. Calculate the
resultant amplitude.
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Answered by
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HERE COMES ANS
FROM GENERAL WAVE FORMULA WE HAVE
Y= ASIN (wt + @)
so IN THIS PERTICULAR CASE WE ARE GIVEN TWO WAVES
1= 3 SIN WT
2 = 4 cos wt
as we know the phase difference between sin and cos will be π /2
but here to calculate the resultant wave which comes to be
A1= 3
A2 = 4
RESULTANT AMPL=
A = √ A1² + A2²
A= √ 9+16
A= 5 cm ❤❤☺❗
brainliest the answer ☺❤
FROM GENERAL WAVE FORMULA WE HAVE
Y= ASIN (wt + @)
so IN THIS PERTICULAR CASE WE ARE GIVEN TWO WAVES
1= 3 SIN WT
2 = 4 cos wt
as we know the phase difference between sin and cos will be π /2
but here to calculate the resultant wave which comes to be
A1= 3
A2 = 4
RESULTANT AMPL=
A = √ A1² + A2²
A= √ 9+16
A= 5 cm ❤❤☺❗
brainliest the answer ☺❤
sahil1531:
that's why I applied this sign
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