Question

The displacement of an object at any instant is given by x= 30+20 t^2 where x is in metre and T in seconds. The accerelation of the object will be?

Pls answer fast. It's urgent

Answer 1

Hey mate, here is your answer:

✓Velocity is Displacement / Time.

✓Acceleration is Velocity / Time.

✓Therefore, Acceleration is Displacement / Time^2

The acceleration of the object is x/ t^2

= { 30 + 20 t^2 }/t ^ 2

= 30/(t^2) + 20 unit/ time sqr.

Hope it helps you.

PLZ MARK AS BRAINLIEST.☝☝

Answer 2

Answer:

The acceleration of the object will be 40 ms⁻².

Explanation:

The displacement of an object is given as,

$x= 30+20 t^2$                  (1)

For acceleration, we know that,

$a=\frac{dv}{dt}$            (2)

Where,

a= acceleration of the object

dv=change in velocity

dt=change in time

For finding acceleration we first need to find the change in velocity. Which is given as,

$dv=\frac{dx}{dt}$      (3)

       

By substituting the value of displacement  in equation (3) we get;

$dv=\frac{30+20 t^2}{dt}=40t$           (4)

         

By placing the required values in equation (2) we get;

$a=\frac{40t}{t}=40ms^-^2$

Hence, the acceleration of the object will be 40 ms⁻².