Question

the displacement of body of mass 3kg under the action of a force is S=(t×t)÷3 metre . the work don in 2s by the same forcein is ( a: 2 , b: 3.8 , c: 5.2 , d: 2.66 )

Answer 1

s=(t^2)/3
differentiating twice with respect to tie
acceleration=2/3
force= ma=2 N
net displacement = 2*2/3=4/3
work done=2*4/3
8/3
2.66
so option d

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