Question

The displacement of particle after time t is given by x =

(k/b2) (1-e-bt), where b and k are constants what is the

acceleration of the particle.......(-_+)only answer needed No faltuu ke comments​

Answer 1

Answer:

x=(k/b^2) ( 1- e -^bt)

a= d^2x / dt^2

a = d/dt ( dx/ dt )

= d/dt ( k / b^2( be - bt ) )

= k/b ( -be -^bt )

a = -ke -^ bt

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