the displacement of particle of mass m in kg moving in one dimensional under the action of force is related to time t by t=√x+3 the displacement of particle when it's velocity is zero will be
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0 m.
Since v= 0 and x= ( t-3)²
X= t2-6t+9
dx/dt- 2t-6
T3 seC.
X=3x3-6x3+9
X=0.
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