Question

the displacement of particle with respect to time is s=3t^3-7t^2+5t+8 where s is in m and t is in s, then acceleration of particle at t=1s is ___. ​

Answer 1

Answer:

4m/s*2

Explanation:

we know : dx/dt = dv

now, by doing differentiation of given equation ,we get : dv = 9t*2-14t+5

now we know a = dv/dt, so again differentiation of dv : a = 18t-14

now we have given the value of t in the question so, acceleration will be: