Question

the displacement of the function of time is given by , x=5+2t+3t² . calculate the value of instantaneous acceleration

Answer 1

see when there is instantaneous word u can always differentiate the equation 
as here distance is given so on differentiating distance twice u can get the acceleration of the object. so we get differentiating once 6t+2
and again on differentiating we get 6 so the object instantaneous acceleration is 6 
pls vote brainliest

Answer 2

The answer is given below :

Given,

displacement,

$x = 5 + 2t + 3 {t}^{2}$

Now, differentiating with respect to t, we get
velocity (v)

$v = \frac{dx}{dt} = (2 + 6t)\:units \:per \:second$

Again, differentiating with respect to t, we get acceleration (a)

$a = \frac{ dv }{dt} \\ \\ = \frac{ {d}^{2}x }{d {t}^{2} } \\ \\ = 6 \: \: units \: per \: {second}^{2}$

Thank you for your question.