Question

The displacement of the particle executing SHM is given by y=A0+asinwt+Bcoswt then amplitude of its ocssilation ?
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Answer 1

Answer:

Explanation:  Equation of resultant SHM y' = y- A0

                          = A0 + Asinwt + Bcoswt - A0

                           = Asinwt+Bcoswt

Resultant amplitude = $\sqrt{} A^{2} sin^{2} wt+B^{2}wt$

                                    =$\sqrt{} A^{2} +B^{2}$