Question

The displacement of the particle is x=2t^2+t^3.velocity at t=2sec is *

1 point

10 m/s

20m/s

30m/s

16 m/s

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Answer 1

Answer:

answer 20mls

Explanation:

no one is here yet but xnh

Answer 2

Answer:

20 m/s

Explanation:

dv=dx/dt

v=d(2t^2+t^3)/dt

v=2*2t^2-1+t^3-1

v=4t+3t^2

on putting the value of t

v=4*2+3(2)^2

v=8+3(4)

v=8+12

v=20

hence velocity is 20m/s