the displacement of two identical particles executing SHM are represented equations
X1=4 sin (10t+π/6) and x2 =5cos (omega t). for what value of Omega energy of a both the particles is same
Answer should be 8
Answers
Answered by
2
❒ᗩᑎՏᗯᗴᖇ-:
8 is the answer.
Answered by
0
Answer:
Energy by a particle in SHM is given by
E=
2
1
mω
2
A
2
; where A is amplitude.
Given amplitude A
1
=4 and A
2
=5
ω
1
=10 and ω
2
=ω
E
1
=
2
1
m
1
ω
1
2
A
1
2
E
2
=
2
1
m
2
ω
2
2
A
2
2
according to question
E
1
=E
2
2
1
m
1
ω
1
2
A
1
2
=
2
1
m
2
ω
2
2
A
2
2
putting values
2
1
m10
2
×4
2
=
2
1
mω
2
2
5
2
1600=25ω
2
ω=8 unit
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