Math, asked by shruti142005, 5 months ago

the displacement of x of a particle moving in One dimension under the action of constant force is related to the time by the equation X =(5t ^2 + 3t-5 ) m where x is in metres and T is in seconds. find the velocity of the particle at 1(t) = 3 s 2(t)=6s ​

Answers

Answered by suhail2070
2

Answer:

1 ) 33 m/s

2 ) 63 m /s

Step-by-step explanation:

x = 5 {t}^{2}  + 3t - 5 \\  \\  \frac{dx}{dt}  = 10t + 3 \\  \\ a) \:  \:  \: at \: t = 3 \\ v = 33 \:  \:  \:   m {s}^{ - 1}  \\  \\  \\ b) \:  \:  \:  \:  \: at \:  \: t = 6 \\ v = 63 \:  \:  \: m {s}^{ - 1}

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