Question

the displacement 'S' of a body of mass 1 kg varies with time 't' as S=2t^2+t, where S is in meters and t is in seconds. the work done by all the forces acting on the body during the time interval t= 1 sec to t=3sec is​

Answer 1

Answer:

Explanation: work done =force *displacement,

force=mass*acceleration ,

according expression,s=2t^2+t......1

s=ut+1/2at^2.......2

by comparing both equations we get , u=1m/s and a=4m/s^2

F=m*a,F=1*4=4N

S=2(3-1)^2+3-1=64 m

work done =4*64=256