Question

the displacement s of an object as a function of time t s= 5t2 +9t calculate the instantaneous velocity of object at t=0

Answer 1

Hello Friend !

You can find the solution to your query below:

We are given that s = 5t² + 9t.

We know that, 

$\frac{ds}{dt}$ = v 

Therefore, differentiating both the sides with respect to time we get,

$\frac{ds}{dt}$ = 10t +9

⇒ v = 10t + 9       ........(1)

Since we have to find velocity at t = 0 

Therefore substituting t = 0 in equation 1 we get,

v = 10(0) + 9

⇒ v = 9 m/s 

This is your answer.

Hope this helps !