the displacement time eq of a particle is given by ×=(t-2)^2 find the distance travelled in 4sec
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Answer:
X =(t-2)^2 = t^2–4t + 4
v = 2t - 4
Distance covered = integ(|v|dt)
= |t^2–4t|
= 4t - t^2 for t = 0 to 2
= t^2 - 4t for t = 2 to 4
= 8 units
Explanation:
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