the displacement time graph for two particles A and B are straight line as shown in figure calculate ratio of velocities of the two particles
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Velocity of first graph divided by velocity of second graph
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I would explain this from the very basics of kinematics.
For a line, slope= (change in y coordinates)/(change in x coordinates)
In displacement time graph, displacement is on Y axis and time on X axis.
Velocity = displacement / time
From both the equation, it can be inferred that in a displacement time graph, slope of the line represents velocity.
Since, slope = tan theta;
Thus V1 / V2 = tan 30 / tan 60 = 1 / √3.
Since the order of ratio is not defined, hence the answer can be either √3 or 1 / √3.
For a line, slope= (change in y coordinates)/(change in x coordinates)
In displacement time graph, displacement is on Y axis and time on X axis.
Velocity = displacement / time
From both the equation, it can be inferred that in a displacement time graph, slope of the line represents velocity.
Since, slope = tan theta;
Thus V1 / V2 = tan 30 / tan 60 = 1 / √3.
Since the order of ratio is not defined, hence the answer can be either √3 or 1 / √3.
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