Question

The Displacement X And Time T For A Particle Are Related To Each Other As. What Is Work Done In First Six Seconds Of Its Motion?

Answer 1

Answer:

Explanation:

Here, t=x−−√+3

∴T−3=x−−√

or x=(t−3)2 …(i)

Velocity, υ=dxdt=2(t−3)

When υ=0,2(t−3)=0,t=3sec.

From (i), x=(t−3)2=(3−3)2=Zero.

Now, at t=0,υ=2(6−3)=−6m/s, and

at t=6s,υ=2(6−3)=−6m/s

Work done = final KE − initial KE

=12m(−6)2−12m(−6)2

Work done = Zero

Answer 2

Answer:

.......................... hope it helps