Physics, asked by Nitinpal3125, 1 year ago

The displacement x if the particle at time t along a straight line is given by x=a-bt+yt2.find the acceleration of the particle.

Answers

Answered by praneshmay
6

We know v=dx/dt

a=dv/dt

x=dx/dt=0+a1+2a2t

a=dv/dt=d/dt (a1+2a2t)

= 0+2a2

Differentiation of constant is 0

So acceleration of particle is 2a2

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