Physics, asked by hh123450, 4 months ago

The displacement x (in meters) of a body varies with time t(in s)as x=-3/5t^2+12t+2. How long the body takes to come to rest​

Answers

Answered by ƒaiŗƴ
1

Given

y= -3/5t^2+12t+2

⁂ v = dy/dt= -6/5t+12

To come to rest , dy/dt= v=0

= -6/5 t+12=0

= 6/5 t = 12

T = 10 sec ✔︎✔︎

Similar questions