Question

The displacement x of a body varies with time t as x=2/3t^2-16t+2 in what time that body comes to rest ?

Answer 1

body will come at rest when velocity will be zero
$x = \frac{2}{3} {t}^{2} - 16t + 2 \\ v = \frac{dx}{dt} = \frac{4}{3} t - 16 = 0 \\ t = 12 \: sec$


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Answer 2

Answer:

Step-by-step explanation:Body will come at rest when v=0

X=2/3t^2 - 16t +2

After derivating

4/3t - 16 =0

t=12 sec