Question

The displacement x of a body varies with time t as x=4t2-15t+25.find the position, velocity,acceleration when t=0.when will the velocity become zero

Answer 1

x=4t^2-15t+25

so. v=8t-15

when velocity is zero

t=15/8
x=4(225/64)-15(15/8)+25
x=900/64-225/8+25
x=900-1800/64 +25

x=-900/64. +25

x=(-900+1600)/64
x=700/64

x=175/16
a=8
here when acceleration is zero when t=0

so x=25