The displacement x of a partice at time t along a straight line is given by x = a - bt + ct^2 . Find the acceleration o the particle
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x = a - bt + ct^2
To find acceleration first we need to find velocity.
V = dx / dt
V = d( a - bt + ct^2) / dt
V = -b + 2ct
Now
A = dV / dt
A = d( -b + 2ct) / dt
A = 2c
Hence acceleration is 2c.
Thanks
To find acceleration first we need to find velocity.
V = dx / dt
V = d( a - bt + ct^2) / dt
V = -b + 2ct
Now
A = dV / dt
A = d( -b + 2ct) / dt
A = 2c
Hence acceleration is 2c.
Thanks
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