Question

The displacement x of a particle along a straight line at time t is given by x = α - βt +π(t^2). Find the acceleration of the particle.​

Answer 1

Answer:

your answer is....................

Explanation:

Given displacement x=α−βt+rt2.........(1)

where α,β and r are constant

Differentiation equation (1) with respect to t, we have

dtdx=dtd(α)−dtd(βt)+dtd(γt2)

dtdx=−β+2γt......(2)

Differentiating equation (2) with respect t again, we get

dt2d2x=−dtd(β)+dxd(2γt)

=2r

We know that acceleration is dt2d2x

∴  The acceleration of particle is given by dt2d2x=2γ