Question

The displacement x of a particle along x-axis is given by x=3+8t+7t^2.obtain its velocity and acceleration at t=2s​

Answer 1

Answer:

Now by ....

differentiation of

this x=3+8t+7t2

we will get velocity

v=8+14t

t=2(given)

v=8+14x2 = 36m/s

now by differentiation of v

we will get a

v=8+14t

now, a=14m/s2

Explanation:

Thankuu

Answer 2

Answer:

v(2)=36, a=14            (CONSTANT)

Explanation:

v=dx/dt = 14t+8

v(2)=14*2+8 = 28+8=36

a= dv/dt = 14 always