The displacement x of a particle along X axis is given by x=3+8t+7t^2 obtain it's velocity and acceleration at t=2s
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- x = 7t² + 8t + 3
- Velocity and acceleration at t = 2 is : ?
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Velocity of the body :
- v = dx/dt
So on differentiating,
⇒ v = d(7t² + 8t + 3)/dt
⇒ v = 14t + 8
Substituting t = 2,
⇒ v = 14(2) + 8
⇒ v = 28 + 8
⇒ v = 36 m/s
Acceleration of the body :
- a = dv/dt
So on differentiating,
⇒ a = d(14t+8)/dt
⇒ a = 14 m/s²
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