The displacement x of a particle along x axis is given by x=3+8t+7t^2. Obtain its velocity and acceleration at t=2seconds.
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Answer:
v(2)=36, a=14 (CONSTANT)
Explanation:
v=dx/dt = 14t+8
v(2)=14*2+8 = 28+8=36
a= dv/dt = 14
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