Question

The displacement x of a particle along x axis is given by x = 8 – 5 t + 20 t^2 . Obtain its velocity and acceleration at t=2 sec.​

Answer 1

Explanation:

Distancex=3+8t+7t

2

,

Velocity v=

dt

dx

=8+14t

v

t=2s

=8+14×2=36ms

−1

,

a=

dt

dv

=14ms

−2