Physics, asked by policevishweshwar, 8 months ago

The displacement x of a particle at any instant is related to
its velocity as v = 2x + 9. Its displacement in 2s is
(A) 5 unit
(B) 8 unit
(C) 1 unit
(D) 2 unit​

Answers

Answered by maheshwarinatraj4121
0

Answer:

option d is the correct answer for the given question.ckeck the given attachment for step by step explanation.

HOPE THIS ANSWER HELPS YOU.......

Attachments:
Answered by sonuvuce
1

The displacement after 2 seconds is 8 unit

Therefore option (B) is correct.

Explanation:

Given:

The relation between displacement x and velocity v as

v = √(2x + 9)

To find out:

Displacement after 2 seconds

Solution:

From the third equation of motion

v^2=u^2+2ax

Given

v^2=2x+9

Comparing we get

u = 3 and a = 1

Therefore, the displacement in t = 2 seconds

s=ut+\frac{1}{2}at^2

\implies s=3\times 2+\frac{1}{2}\times 1\times 2^2

\implies s=6+2=8 unit

Hope this answer is helpful.

Know More:

Q: The displacement(in metres) of a particle moving along x-axis is given by x=18t+5t^2.Calculate: i)instantaneous velocity at t=2s ii)instantaneous acceleration.

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Q: The displacement x of a particle at the instant when its velocity is v is given by v = \sqrt{3x+16}. Its acceleration and initial velocity are

(a) 1.5 units, 4 units

(b) 3 units, 4 units

(c) 16 units, 1.6 units

(d) 16 units, 3 units

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