Question

the displacement x of a particle at any instant is related to its velocity v=root of 2x+9 its displacement in 2s is

Answer 1

Answer:

Displacement of the particle is X (Given )

velocity is root X+9

Explanation:

V2=2x+9

V2-9=2x

(U2=9)got

comparing with the equation of velocity

(V2-U2=2as)

2ax=2x

a =2x/2x

a=1

U =9

U =√9

U =3m /s

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Answer 2

The displacement after 2 seconds is 8 unit

Explanation:

Given:

The relation between displacement x and velocity v as

v = √(2x + 9)

To find out:

Displacement after 2 seconds

Solution:

From the third equation of motion

$v^2=u^2+2ax$

Given

$v^2=2x+9$

Comparing we get

u = 3 and a = 1

Therefore, the displacement in t = 2 seconds

$s=ut+\frac{1}{2}at^2$

$\implies s=3\times 2+\frac{1}{2}\times 1\times 2^2$

$\implies s=6+2=8$ unit

Hope this answer is helpful.

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