Question

The displacement x of a particle at the instant when its velocity is v is given by $v = \sqrt{3x+16}$. Its acceleration and initial velocity are
(a) 1.5 units, 4 units
(b) 3 units, 4 units
(c) 16 units, 1.6 units
(d) 16 units, 3 units

Answer 1

I think answer will be

b)3 units, 4 units

Answer 2

Answer:

1.5 and 4 units

Explanation:

Displacement of particle = x (Given)

Velocity = v = √3x+16 ( Given)

or v² = 3x+16

or v²−16 =3x

Comparing with the equation of velocity = v²−u²=2as

On solving, We will get u = 4 units

Thus,

2a =3

a = 1.5units

Thus, the acceleration and initial velocity are 1.5 units and 4 units