Question

The displacement x of a particle is dependent on time t according to the relation x = 3-5t+2t^2. If t is measured in sec and x in min. Find it's velocity at t = 2s and acceleration at t = 4 s

Answer 1

Explanation:

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Answer 2

The velocity of the particle at t = 2 s is 3 m/s and the acceleration at t = 4 s is $4\ m/s^2$.

Explanation:

The displacement x of a particle is dependent on time t according to the relation as :

$x=3-5t+2t^2$

Velocity of the particle,

$v=\dfrac{dx}{dt}$

$v=\dfrac{d(3-5t+2t^2)}{dt}$

$v=-5+4t$

At t = 2 s

$v=-5+4(2)$

v = 3 m/s

Acceleration of the particle is given by,

$a=\dfrac{dv}{dt}$

$a=\dfrac{d(-5+4t)}{dt}$

$a=4\ m/s^2$

So, the velocity of the particle at t = 2 s is 3 m/s and the acceleration at t = 4 s is $4\ m/s^2$. hence, this is the required solution.

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