The displacement x of a particle is dependent on time t according to the relation x = 3-5t+2t^2. If t is measured in sec and x in min. Find it's velocity at t = 2s and acceleration at t = 4 s
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Answered by
0
Answer:
V
y
=
dt
dy
=
dx
dy
×
dt
dx
=x
3
×
2
1
=
16
t
3
at t=4
3
V
y
=
16
4×4×4
=4m/s
V
x
=
2
1
m/s
Velocity of particle is V=V
x
i
^
+V
y
j
^
=
2
1
i
^
+4
j
^
Answered by
0
Answer:
The velocity of the particle at t = 2 s is 3 m/s and the acceleration at t = 4 s is .
Explanation:
Velocity of the particle,
At t = 2 s
v = 3 m/s
Acceleration of the particle,
At t = 4s
a = 4m/s
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