Question

The displacement x of a particle moving in one dimension under the action of constant force is related to time t by the equation t= √x +3, where
x is in metres and t is in seconds. Find the displacement of the particle when its velocity is zero.
(a) Zero (b) 12 m (c) 6 m (d) 18 m​

Answer 1

Answer:

(a) 0

Explanation:

t= √x +3

√x = t - 3 square both sides

x = t^2 - 6t + 9

now dx/dt = 2t - 6

i.e, v = 2t - 6

0 = 2t - 6 (at v=0)

t = 3sec

now,

from eq t= √x +3

3 = √x + 3

x = 0

Answer 2

Answer:

when velocity is 0, then displacement is also 0

Explanation:

velocity =displacement/time

0           = x/t

0            = x

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