Question

The displacement ‘x’ of a particle moving in one dimension is related to time t by the relation x = √(2t 2 – 3t), where x is in metre and t in second. Find the displacement of the particle when its velocity is zero.

Answer 1

t = √x+3

√x = t-3

x = t² - 6t + 9 

dx/dt is the velocity

dx/dt = 2t -6

v = 0

2t-6 = 0 

which will give us 3 so t = 3

at t = 3

x = 3-3

so there will be 0 displacement.