Question

The displacement x of a particle of mass m kg miving in one dimension under the action of a force is related to the time t by the equation t=√x +3 where x is in meters and t is in seconds .the work done by the force in the first six seconds in jouls is

Answer 1

Answer:

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Answer 2

Solution:

★ Given:

➜ The displacement x of a particle of mass m kg miving in one dimension under the action of a force is related to the time t by the equation t = √x + 3 where x is in meters and t is in seconds .

★ Find:

➜ The work done by the force in the first six seconds in jouls is.

★ Step-by-step:

➜ t = √x + 3

➜ t - 3 = √x

★ Squaring both the sides:

➜ (t - 3)² = x

➜ x = (t² + 9 - 6t)

★ Diff .w.r to x:

➜ dx/dt = d/at (t² + g6t)

➜ 2 t + 0 - 6 CI)

➜ dx/dt = (2t - 0)

★ Diff .w.r to x:

➜ dx²/dd² = d/dt (2t - 6)

➜ 2(1) - 0 = 2

★ Displacement in seconds:

➜ (0 - 3)² - g

➜ g - g = 0

★ Work done:

➜ F × S

➜ F × 0 = 0

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