Question

The displacement x of a particle of mass m kg moving in one dimension, under the action of a force, is related to the time t by the equation t=4x+3 where x is in meters and t is in seconds. The work done by the force in the first six seconds in joules is

Answer 1

Answer:

0 J

Explanation:

X=(t-3)/4

first differentiation of x is 0.25

Work done is equal to change in kinetic energy but here velocity is constant hence there will be no change in kinetic energy. So work done is 0