Question

the displacement x of a particle time t as X equal to 4 x square - 15t + 25 position velocity e and acceleration of the particle at t equal to zero when when will the velocity of a particle becomes zero ​

Answer 1

Explanation:

to find position of particle t=0 in given equation we get x=25

to find velocity differentiate with respect to tea we get Dx/dt=8t-15 now put t=0 we get velocity =-15

to find acceleration differentiate equation of velocity w. r. t we get d^2×/dt^2=8

as acceleration remains constant it is uniform acceleration

now consider equation of velocity dx/dt=8t-15

Putt v=0 we get 8t= 15 t=15/8 at t=15/8 velocity

will be zero .

hope you have got the answer if yes then please Brainliest the answer .