Question

The displacement x of a particle varies with time t as x=4t2
-15t+25. Find theposition, velocity acceleration of the particle at t=0. When will the velocityof particle become zero? Can we call the motion of the particle as one withuniform acceleration?

Answer 1

position (x)=4t²-15t+25
at t=0
x=25

v(velocity)=8t-15
at t=0
v=-15

a(acceleration)=8

the velocity of particle will become zero at
v=8t-15
v=0
8t-15=0
8t=15
t=15/8