Question

the displacement x of a particle varies with time t is x=4t2-15t++25 find the position velocity and acceleration of the particle at t =0​

Answer 1

Answer:

25m

-15 m/s

8 m/s2

Explanation:

x=4t2-15t+25

v=dx/dt=8t-15 and v at t=0 is -15 m/s

a=dv/dt=8 and a at t=0 is 8 m/s2

Answer 2

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