Question

the displacement x of a particles moving in dimensions is releated to time t by the relation x = $2t2-3t$ where x is in metre and t in second find the displacement of the particles when its velocity is zero

Answer 1

Answer:

9/8m

Explanation:

Given x =2t²-3t

V = dx/dt = d(2t²-3t)/dt

v = 4t - 3

But given , v = 0

0 = 4t - 3

t = 3/4

displacement at 3/4 sec

x = (2t²-3t)

x = 2(3/4)²-3(3/4)

x = 2* 9/16 - 9/4

x = 9/8-9/4

x = 9-18/8 = 9/8 m Answer

Hope it's helpful