Question

The displacement x of an object is given as a function of time,
$x = 2t + {3t}^{2}$
Calculate the instantaneous velocity of the object at t = 2s ​

Answer 1

Solution:

$x = 2t + {3t}^{2}$

$v = \frac{dx}{dt} = 2 + 6t$

Substituting the value of t as 2, we get

$v = 2 + 6 \times 2$

v = 14 m/s

So, the instantaneous velocity of the object at time T =2 s is 14 m/s.

Hope this will help you ❤

Answer 2

Explanation:

Given

x = 2t + 3t²

V = dx/dt = 2 + 6t

now substitute t = 2 sec

v = 2 + (6 × 2)

According to BODMAS rule

v = 2 + 12

v = 14 m/sec

Instantaneous velocity = 14 m/s