Physics, asked by madhurayadiyal210, 5 days ago

The displacement (x) - time (t) graph of a particle moving along a straight line is shown in graph. The ratio of magnitude of velocities of particle for two regions OA and AC (Voa/Voc) is


​1:2
1:3
2:1
3:1

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Answers

Answered by rishaduro
10

Answer is 3:1

Just need idea of slope

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Answered by amitnrw
1

Given : The displacement (x) - time (t) graph of a particle moving along a straight line is shown in graph.

To find : The ratio of magnitude of velocities of particle for two regions OA and AC (Voa/Vac)

Solution:

Velocity is the rate of change of displacement

Hence slope of OA  will give Voa

Voa  =  Tan60°

=> Voa  =  √3

=> | Voa | =  √3

slope of AC  will give Vac

Vac = -Vca

Vac  =-( -Tan30°)     ( ∵ tan (180° - θ) = - tan θ)

=> Vac =  Tan30°

=> Vac  = 1/√3

=> | Vac | =  1/√3

The ratio of magnitude of velocities of particle for two regions OA and AC (Voa/Vac)  = √3 : 1/√3

= 3 :  1

|Voa / Vac | = 3 : 1

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