Question

The dissociation constant of a weak acid HA and weak base BOH are 2×10-5 and 5×10-6 respectively.The equilibrium constant for the neutralization reaction of the two is ( ignore hydrolysis of resulting salt)

Answer 1

A neutralization reaction is when an acid and base react to form water and a salt in the presence of hydrogen ions. For the neutralization reaction for weak acid and weak base, the expression of the equilibrium constant K is given as

K= Ka * Kb/Kw

HA + BOH ------------------>  B+ + A- + H2O

K = [B+][A-][H2O]/[HA][BOH]

 = [B+][OH-]/[BOH] *  [H+][A-]/[HA] *  [H2O]/[H+][OH-] = Kb *  Ka  /  Kw

Weak acid HA, Ka=2×10-5 and weak base BOH, KB=5×10-6Kh=Ka×KbKh=Keq=Ka×KbKeq= (2×10-5)(5×10-6)Keq=10×10-11Keq=1×10-10

Answer 2

Answer:

10^4

here's the answer and hope this helps you.