The dissociation constant of an acid HA is Ka= 1 10-5. The pH of 0.1 molar
solution of the acid will be
(A.) Five (B.) Four (C.) Three (D.) One
suneeshkamat19:
correction: 1*10^-5
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Answer:
3
Explanation:
For a weak acid, [H+ ]=root of Ka ×c
The dissociation constant is 1×10 ^−5 and the concentration is 0.1 M.
Substitute values in the above expression,
[H+]= 1×10 ^−5 x0.1
=1×10 ^−3
pH=−log[H + ]=−log10 ^−3
=3.
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Answer:
Why are you obsessed with chemistry
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