Chemistry, asked by suneeshkamat19, 9 months ago

The dissociation constant of an acid HA is Ka= 1 10-5. The pH of 0.1 molar

solution of the acid will be

(A.) Five (B.) Four (C.) Three (D.) One​


suneeshkamat19: correction: 1*10^-5

Answers

Answered by midhunamurali2019
0

Answer:

3

Explanation:

For a weak acid, [H+ ]=root of  Ka ×c

The dissociation constant is 1×10 ^−5  and the concentration is 0.1 M.

Substitute values in the above expression,

[H+]=  1×10  ^−5 x0.1

​  =1×10 ^−3

pH=−log[H + ]=−log10  ^−3

     =3.

Answered by jadstech
0

Answer:

Why are you obsessed with chemistry

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