The dissociation constant of base BOH à B+ + OH-
Option
ОООС
окЬ [ОН-1 (B+] [Вон)
Kb = (вон] / [ОН-1 (B+)
Kb [он.] / [Вон] [Вт)
Kb = [B+] / [BOH] [ОНН)
Answers
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Answer:
jdbc xjbxjsnbdbxjxbvdbndnxbdbdhcbd
Explanation:
b,jxbbsbsndn.... -$+%-$....
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