Chemistry, asked by hatyjamuratkulyeva, 4 months ago

The dissociation constant of base BOH à B+ + OH-
Option
ОООС
окЬ [ОН-1 (B+] [Вон)
Kb = (вон] / [ОН-1 (B+)
Kb [он.] / [Вон] [Вт)
Kb = [B+] / [BOH] [ОНН)

Answers

Answered by anas824211

0

Answer:

jdbc xjbxjsnbdbxjxbvdbndnxbdbdhcbd

Explanation:

b,jxbbsbsndn.... -$+%-$....

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