Chemistry, asked by neh1237, 14 days ago

The dissociation constant of the complex ion [Cu(NH3) 4]^2+ is 1.0×10^_12.calculate its stability constant?​

Answers

Answered by llElegantlavenderll
6

Answer:

Dissociation constant is the reciprocal of the stability constant (k=1/β).

Overall complex dissociation equilibrium constant, k=

β

4

1

k=

2.1×10

13

1

k=4.76×10

−14

Answered by angel163853
3

Explanation:

Explanation: Dissociation constant is the reciprocal of the stability constant (β = 1/K). Overall complex dissociation equilibrium constant

k = 4.76 \times  {10}^{ - 14}

Similar questions